1

want to maximize surplus (sum of benefit for both seller and buyer)

first-price auction: difficult to analyze, will do so in ch 2/6

ascending-price auction strategy:

  • increase price from 0 until all but one person drops out, then give that last person the current price
  • assume that agents act to maximize their own benefit, then clearly there is no benefit to dropping out when price < WTP
  • therefore agent ๐‘– will drop out at price ๐‘ฃ๐‘–, so agent 1 will gain ๐‘ฃ1โˆ’๐‘ฃ2 and seller will gain ๐‘ฃ2, thus achieving the maximum possible benefit of ๐‘ฃ1

second-highest bid strategy:

  • have everyone bid, offer second-highest price to highest bidder
  • importantly, this encourages everyone to bid truthfully
  • prove sketch: fix x to be the max of everyone elseโ€™s bids. if x < v_i, any bid >= x is optimal. and if v_i < x, any bid โ‡ x is optimal. therefore, v_i is always an optimal bid (and the only bid that is optimal in all scenarios)

maximizing consumer surplus rather than surplus is difficult, as if ๐‘ฃ๐‘– is constant, lottery is best: but if ๐‘ฃ1=1 and all other ๐‘ฃ๐‘–=0, second-highest bid is better. In general, no single mechanism works, whereas when maximizing surplus, second-highest bid is clearly optimal.

2

let ๐‘ฅ and ๐‘ denote whether an agent receives a good and their payment, respectively

in order to be in equilibrium:

๐‘ฅ must be monotone as bid increases

intuitively, this makes sense: why would you bid higher only to get less chance of getting the item?

RSOP

b/c price given to each person doesnโ€™t depend on what they bid, itโ€™s clearly optimal for them to always tell the truth

1/4 lower bound: consider 2 bidders with ๐‘ฃ1>๐‘ฃ2. With probability 12 they are in different sets, and therefore seller gains revenue of ๐‘ฃ2 with probability 12, so expected revenue is ๐‘ฃ22, which is 14 of maximum revenue 2๐‘ฃ2.

4.68 bound paper: ๐‘†๐‘— = how many of the first ๐‘— bidders are in the sample ๐‘๐‘— = fraction of first ๐‘— bidders in market to sample ๐‘ = min๐‘๐‘—

  • 1/15 proof considers scenarios where ๐‘โ‰ฅ13, and shows that this occurs with high probability

๐ธ๐›ผ โ‡’ probability that the maximum ratio of ๐‘†๐‘—๐‘— does not exceed ๐›ผ

๐ธ๐‘‡๐›ผ and ๐ธ๐‘‡โ€ฒ๐›ผ are positively correlated for any ๐‘‡, ๐‘‡โ€ฒ