by creating a single element set for each number from , we can determine whether has the highest bit on or off
then we can create two element sets, where each element has the second bit off
we can’t do that many checks though…
by creating a single element set for each number from , we can determine whether has the highest bit on or off
then we can create two element sets, where each element has the second bit off
we can’t do that many checks though…