First, observe that for two slimes 𝑢 and 𝑣 with distinct 𝐶𝑢 and 𝐶𝑣, exactly one of them can eat the other (if 𝐶𝑢=𝐶𝑣, neither can eat the other). In particular, 𝑢 can eat 𝑣 if 𝐶𝑣𝐶𝑢𝐾(mod2𝐾+1). Also note that we can consider each component in 𝐺\{1} independently, since no slimes can eat through 1. In particular, for each component, we care about whether 1 can eventually eat it or not.

To build some intuition, here are some visuals for cases with 𝐾=3: *WLOG, we will assume 𝐶1=0.

The first case is impossible because 0 cannot eat any of 4, 5, or 6.

However, this is remedied with the presence of the 1 in the second case, which can be eaten by 0 but can also eat 4, which in turn can eat 5 and 6. A possible sequence of events is shown above.

Still, in the third case, we see that the presence of an intermediate such as 1 does not necessarily guarantee success. Indeed, this case is impossible because 5 and 6 can only be eaten if 1 is eaten through first. Therefore, the remaining value will be >3, making it yet again impossible for 0 to continue eating. However, if the middle value were 3, or if all the outer values were changed to 4, this would again be possible.

To formalize this a little bit, let 𝑟 be the node in the component with the largest 𝐶𝑟 satisfying 1𝐶𝑟𝑘: this is the largest possible “intermediate”, which we will try to use to eat larger values.

For a concrete example, if 𝐶𝑟=𝑘, we can actually always win by the following procedure:

  1. While there exists 𝑢 with 𝐶𝑢>𝑘, find one such 𝑢 adjacent to 𝑣 with 𝐶𝑣𝐶𝑢. Since there exists 𝐶𝑟=𝑘, such a (𝑢,𝑣) pair is guaranteed to exist. Then, have one of (𝑢,𝑣) eat the other. Importantly, note that 𝑟 itself can never be eaten by this procedure.
  2. Now, there exists only 𝐶𝑖𝑘, which can all be eaten by node 1 which has 𝐶1=0.

So in this example, there are only two categories of slimes: 𝐶𝑖𝑘, which we’ll refer to as P-type, and 𝐶𝑖>𝑘, which we’ll refer to as Q-type (in order to be consistent with the official editorial). However, if 𝐶𝑟<𝑘, we must introduce an additional R-type, which satisfies 𝐶𝑟+𝑘<𝐶𝑖.