The exponential distribution is defined such that its growth rate at any instant is equal to its value. It’s also well known that exp(π‘₯)=βˆ‘π‘₯π‘˜π‘˜!. There’s a nice combinatorial way to connect these two definitions:

First, consider the discrete version of exp(π‘₯), 2π‘₯. We can find 2π‘₯ by the following process: let 𝑆0 be {{}} (that is, an empty set of sets). Then, define 𝑆𝑖 for 𝑖>0 to be π‘†π‘–βˆ’1βˆͺ{𝑠βˆͺ𝑖|π‘ βˆˆπ‘†π‘–βˆ’1}. That is, we take every set from π‘†π‘–βˆ’1, then decide whether to add 𝑖 into it or not. Here a few values of 𝑆𝑖:

  • 𝑆0={{}}
  • 𝑆1={{},{1}}
  • 𝑆2={{},{1},{2},{1,2}}

We can see how this simulates a growth rate equal to value, since clearly, |𝑆𝑖+1βˆ’π‘†π‘–|=|𝑆𝑖|. Therefore, |𝑆𝑖|=2𝑖 as desired. However, 𝑆𝑖 is also just the number of ways to select a subset of the integers in [0,𝑖]. How can we express this in a continuous fashion?

Loosely speaking, the β€œnumber of ways” to select π‘˜ numbers in the range [0,π‘₯] should just be π‘₯π‘˜π‘˜! (since in the continuous case, there is 0 chance of picking two equal numbers). Therefore, summing over all possible values of π‘˜, we arrive at our desired expression.

Let’s formalize β€œnumber of ways.” Note that instead of |𝑆𝑖+1βˆ’π‘†π‘–|=|𝑆𝑖|, we now want |𝑆π‘₯+dπ‘₯βˆ’π‘†π‘₯|=|𝑆π‘₯|dπ‘₯. This means we need to slightly redefine |𝑆𝑖|. Currently, it’s simply defined as the number of sets in 𝑆𝑖, or βˆ‘π‘ βˆˆπ‘†π‘–1, but instead we want

|𝑆𝑖|=βˆ‘π‘ βˆˆπ‘†π‘–(dπ‘₯)|𝑠|

That is, sets are now assigned a β€œweight” which decreases as the set size increases. It can be shown that under this definition, the loose argument made above can be made precise.

This definition of |𝑆𝑖| can also be interpreted probabilistically by defining a random process in which each interval [π‘₯,π‘₯+dπ‘₯] is selected independently with probability dπ‘₯. This corresponds to a Poisson process with πœ†=1. In particular, the chance of selecting exactly π‘˜ intervals is just

π‘₯π‘˜π‘˜!|𝑆π‘₯|=π‘’βˆ’π‘₯π‘₯π‘˜π‘˜!

as expected (|𝑆π‘₯| appears in the denominator of the LHS as a normalizing factor).